2x^2=238

Solution for 2x^2=238 equation:

2x^2=238

We move all terms to the left:

2x^2-(238)=0

a = 2; b = 0; c = -238;
Δ = b2-4ac
Δ = 02-4·2·(-238)
Δ = 1904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1904}=\sqrt{16*119}=\sqrt{16}*\sqrt{119}=4\sqrt{119}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{119}}{2*2}=\frac{0-4\sqrt{119}}{4}
=-\frac{4\sqrt{119}}{4}
=-\sqrt{119}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{119}}{2*2}=\frac{0+4\sqrt{119}}{4}
=\frac{4\sqrt{119}}{4}
=\sqrt{119}
$